Solve 2^2-0.002^32^3

$${ 2 }^{ 2 } - { 0.002 }^{ 3 } { 2 }^{ 3 }$$

Evaluate

$$3.999999936$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$4-0.002^{3}\times 2^{3}$$

Calculate 0.002 to the power of 3 and get 0.000000008.

$$4-0.000000008\times 2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$4-0.000000008\times 8$$

Multiply 0.000000008 and 8 to get 0.000000064.

$$4-0.000000064$$

Subtract 0.000000064 from 4 to get 3.999999936.

$$3.999999936$$

Factor

$$\frac{3 \cdot 31 \cdot 672043}{2 ^ {3} \cdot 5 ^ {9}} = 3\frac{15624999}{15625000} = 3.999999936$$