Solve 2^2=4^2+2xy

$${ 2 }^{ 2 } = { 4 }^{ 2 } +2xy$$

Solve for x

$$x=-\frac{6}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$4=4^{2}+2xy$$

Calculate 4 to the power of 2 and get 16.

$$4=16+2xy$$

Swap sides so that all variable terms are on the left hand side.

$$16+2xy=4$$

Subtract 16 from both sides.

$$2xy=4-16$$

Subtract 16 from 4 to get -12.

$$2xy=-12$$

The equation is in standard form.

$$2yx=-12$$

Divide both sides by 2y.

$$\frac{2yx}{2y}=-\frac{12}{2y}$$

Dividing by 2y undoes the multiplication by 2y.

$$x=-\frac{12}{2y}$$

Divide -12 by 2y.

$$x=-\frac{6}{y}$$

Solve for y

$$y=-\frac{6}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$4=4^{2}+2xy$$

Calculate 4 to the power of 2 and get 16.

$$4=16+2xy$$

Swap sides so that all variable terms are on the left hand side.

$$16+2xy=4$$

Subtract 16 from both sides.

$$2xy=4-16$$

Subtract 16 from 4 to get -12.

$$2xy=-12$$

Divide both sides by 2x.

$$\frac{2xy}{2x}=-\frac{12}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$y=-\frac{12}{2x}$$

Divide -12 by 2x.

$$y=-\frac{6}{x}$$