Solve 2^0+-6^6*4^-3--2^3-{left(1/{4^}right)}^-1

$${ 2 }^{ 0 } + { -6 }^{ 6 } \times { 4 }^{ -3 } - { -2 }^{ 3 } - { \left( \frac{ 1 }{ { 4 }^{ } } \right) }^{ -1 }$$

Evaluate

$$734$$

Solution Steps

Calculate 2 to the power of 0 and get 1.

$$1+\left(-6\right)^{6}\times 4^{-3}-\left(-2\right)^{3}-\left(\frac{1}{4^{1}}\right)^{-1}$$

Calculate -6 to the power of 6 and get 46656.

$$1+46656\times 4^{-3}-\left(-2\right)^{3}-\left(\frac{1}{4^{1}}\right)^{-1}$$

Calculate 4 to the power of -3 and get \frac{1}{64}.

$$1+46656\times \frac{1}{64}-\left(-2\right)^{3}-\left(\frac{1}{4^{1}}\right)^{-1}$$

Multiply 46656 and \frac{1}{64} to get 729.

$$1+729-\left(-2\right)^{3}-\left(\frac{1}{4^{1}}\right)^{-1}$$

Add 1 and 729 to get 730.

$$730-\left(-2\right)^{3}-\left(\frac{1}{4^{1}}\right)^{-1}$$

Calculate -2 to the power of 3 and get -8.

$$730-\left(-8\right)-\left(\frac{1}{4^{1}}\right)^{-1}$$

The opposite of -8 is 8.

$$730+8-\left(\frac{1}{4^{1}}\right)^{-1}$$

Add 730 and 8 to get 738.

$$738-\left(\frac{1}{4^{1}}\right)^{-1}$$

Calculate 4 to the power of 1 and get 4.

$$738-\left(\frac{1}{4}\right)^{-1}$$

Calculate \frac{1}{4} to the power of -1 and get 4.

$$738-4$$

Subtract 4 from 738 to get 734.

$$734$$

Factor

$$2\times 367$$