Solve 16^2+12*16+16+10*16^-1+3*16^-2

$${ 16 }^{ 2 } +12 \times 16+16+10 \times { 16 }^{ -1 } +3 \times { 16 }^{ -2 }$$

Evaluate

$$\frac{118947}{256}=464.63671875$$

Solution Steps

Calculate 16 to the power of 2 and get 256.

$$256+12\times 16+16+10\times 16^{-1}+3\times 16^{-2}$$

Multiply 12 and 16 to get 192.

$$256+192+16+10\times 16^{-1}+3\times 16^{-2}$$

Add 256 and 192 to get 448.

$$448+16+10\times 16^{-1}+3\times 16^{-2}$$

Add 448 and 16 to get 464.

$$464+10\times 16^{-1}+3\times 16^{-2}$$

Calculate 16 to the power of -1 and get \frac{1}{16}.

$$464+10\times \frac{1}{16}+3\times 16^{-2}$$

Multiply 10 and \frac{1}{16} to get \frac{5}{8}.

$$464+\frac{5}{8}+3\times 16^{-2}$$

Add 464 and \frac{5}{8} to get \frac{3717}{8}.

$$\frac{3717}{8}+3\times 16^{-2}$$

Calculate 16 to the power of -2 and get \frac{1}{256}.

$$\frac{3717}{8}+3\times \frac{1}{256}$$

Multiply 3 and \frac{1}{256} to get \frac{3}{256}.

$$\frac{3717}{8}+\frac{3}{256}$$

Add \frac{3717}{8} and \frac{3}{256} to get \frac{118947}{256}.

$$\frac{118947}{256}$$

Factor

$$\frac{3 \cdot 31 \cdot 1279}{2 ^ {8}} = 464\frac{163}{256} = 464.63671875$$