Solve 10.33^2=3^2+9^2-2(3)(9)

$${ 10.33 }^{ 2 } = { 3 }^{ 2 } + { 9 }^{ 2 } -2(3)(9)$$

Verify

Solution Steps

Calculate 10.33 to the power of 2 and get 106.7089.

$$106.7089=3^{2}+9^{2}-2\times 3\times 9$$

Calculate 3 to the power of 2 and get 9.

$$106.7089=9+9^{2}-2\times 3\times 9$$

Calculate 9 to the power of 2 and get 81.

$$106.7089=9+81-2\times 3\times 9$$

Add 9 and 81 to get 90.

$$106.7089=90-2\times 3\times 9$$

Multiply 2 and 3 to get 6.

$$106.7089=90-6\times 9$$

Multiply 6 and 9 to get 54.

$$106.7089=90-54$$

Subtract 54 from 90 to get 36.

$$106.7089=36$$

Compare 106.7089 and 36.

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