Solve 10^2=8^2*x^2

$${ 10 }^{ 2 } = { 8 }^{ 2 } \times { x }^{ 2 }$$

Solve for x

$$x = \frac{5}{4} = 1\frac{1}{4} = 1.25$$

$$x = -\frac{5}{4} = -1\frac{1}{4} = -1.25$$

Steps Using Difference of Squares

Calculate 10 to the power of 2 and get 100.

$$100=8^{2}x^{2}$$

Calculate 8 to the power of 2 and get 64.

$$100=64x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$64x^{2}=100$$

Subtract 100 from both sides.

$$64x^{2}-100=0$$

Divide both sides by 4.

$$16x^{2}-25=0$$

Consider 16x^{2}-25. Rewrite 16x^{2}-25 as \left(4x\right)^{2}-5^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(4x-5\right)\left(4x+5\right)=0$$

To find equation solutions, solve 4x-5=0 and 4x+5=0.

$$x=\frac{5}{4} x=-\frac{5}{4}$$

Steps by Finding Square Root

Calculate 10 to the power of 2 and get 100.

$$100=8^{2}x^{2}$$

Calculate 8 to the power of 2 and get 64.

$$100=64x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$64x^{2}=100$$

Divide both sides by 64.

$$x^{2}=\frac{100}{64}$$

Reduce the fraction \frac{100}{64} to lowest terms by extracting and canceling out 4.

$$x^{2}=\frac{25}{16}$$

Take the square root of both sides of the equation.

$$x=\frac{5}{4} x=-\frac{5}{4}$$

Steps Using the Quadratic Formula

Calculate 10 to the power of 2 and get 100.

$$100=8^{2}x^{2}$$

Calculate 8 to the power of 2 and get 64.

$$100=64x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$64x^{2}=100$$

Subtract 100 from both sides.

$$64x^{2}-100=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 64 for a, 0 for b, and -100 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 64\left(-100\right)}}{2\times 64}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 64\left(-100\right)}}{2\times 64}$$

Multiply -4 times 64.

$$x=\frac{0±\sqrt{-256\left(-100\right)}}{2\times 64}$$

Multiply -256 times -100.

$$x=\frac{0±\sqrt{25600}}{2\times 64}$$

Take the square root of 25600.

$$x=\frac{0±160}{2\times 64}$$

Multiply 2 times 64.

$$x=\frac{0±160}{128}$$

Now solve the equation x=\frac{0±160}{128} when ± is plus. Reduce the fraction \frac{160}{128} to lowest terms by extracting and canceling out 32.

$$x=\frac{5}{4}$$

Now solve the equation x=\frac{0±160}{128} when ± is minus. Reduce the fraction \frac{-160}{128} to lowest terms by extracting and canceling out 32.

$$x=-\frac{5}{4}$$

The equation is now solved.

$$x=\frac{5}{4} x=-\frac{5}{4}$$