Solve 1^3-9*5^2+15*5-3

$${ 1 }^{ 3 } -9 \times { 5 }^{ 2 } +15 \cdot 5-3$$

Evaluate

$$-152$$

Solution Steps

Calculate 1 to the power of 3 and get 1.

$$1-9\times 5^{2}+15\times 5-3$$

Calculate 5 to the power of 2 and get 25.

$$1-9\times 25+15\times 5-3$$

Multiply 9 and 25 to get 225.

$$1-225+15\times 5-3$$

Subtract 225 from 1 to get -224.

$$-224+15\times 5-3$$

Multiply 15 and 5 to get 75.

$$-224+75-3$$

Add -224 and 75 to get -149.

$$-149-3$$

Subtract 3 from -149 to get -152.

$$-152$$

Factor

$$-152$$