Solve 0.056^2+0.01^2+0.01^2+0.002^2+{0.022}^2

$${ 0.056 }^{ 2 } + { 0.01 }^{ 2 } + { 0.01 }^{ 2 } + { 0.002 }^{ 2 } + { 0.022 }^{ 2 }$$

Evaluate

$$0.003824$$

Solution Steps

Calculate 0.056 to the power of 2 and get 0.003136.

$$0.003136+0.01^{2}+0.01^{2}+0.002^{2}+0.022^{2}$$

Calculate 0.01 to the power of 2 and get 0.0001.

$$0.003136+0.0001+0.01^{2}+0.002^{2}+0.022^{2}$$

Add 0.003136 and 0.0001 to get 0.003236.

$$0.003236+0.01^{2}+0.002^{2}+0.022^{2}$$

Calculate 0.01 to the power of 2 and get 0.0001.

$$0.003236+0.0001+0.002^{2}+0.022^{2}$$

Add 0.003236 and 0.0001 to get 0.003336.

$$0.003336+0.002^{2}+0.022^{2}$$

Calculate 0.002 to the power of 2 and get 0.000004.

$$0.003336+0.000004+0.022^{2}$$

Add 0.003336 and 0.000004 to get 0.00334.

$$0.00334+0.022^{2}$$

Calculate 0.022 to the power of 2 and get 0.000484.

$$0.00334+0.000484$$

Add 0.00334 and 0.000484 to get 0.003824.

$$0.003824$$

Factor

$$\frac{239}{2 ^ {2} \cdot 5 ^ {6}} = 0.003824$$