Solve -4^2-4-1left(-k+2right)=0

$${ -4 }^{ 2 } -4-1 \left( -k+2 \right) = 0$$

Solve for k

$$k=-10$$

Steps for Solving Linear Equation

Calculate -4 to the power of 2 and get 16.

$$16-4-\left(-k+2\right)=0$$

Subtract 4 from 16 to get 12.

$$12-\left(-k+2\right)=0$$

To find the opposite of -k+2, find the opposite of each term.

$$12-\left(-k\right)-2=0$$

Subtract 2 from 12 to get 10.

$$10-\left(-k\right)=0$$

Subtract 10 from both sides. Anything subtracted from zero gives its negation.

$$-\left(-k\right)=-10$$

Divide both sides by -1.

$$-k=\frac{-10}{-1}$$

Fraction \frac{-10}{-1} can be simplified to 10 by removing the negative sign from both the numerator and the denominator.

$$-k=10$$

Multiply both sides by -1.

$$k=-10$$