Solve -3^2left(-6+2right)^4div2(-2)-4^3

$${ -3 }^{ 2 } { \left(-6+2 \right) }^{ 4 } \div 2(-2) { -4 }^{ 3 }$$

Evaluate

$$147456$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$\frac{9\left(-6+2\right)^{4}}{2}\left(-2\right)\left(-4\right)^{3}$$

Add -6 and 2 to get -4.

$$\frac{9\left(-4\right)^{4}}{2}\left(-2\right)\left(-4\right)^{3}$$

Calculate -4 to the power of 4 and get 256.

$$\frac{9\times 256}{2}\left(-2\right)\left(-4\right)^{3}$$

Multiply 9 and 256 to get 2304.

$$\frac{2304}{2}\left(-2\right)\left(-4\right)^{3}$$

Divide 2304 by 2 to get 1152.

$$1152\left(-2\right)\left(-4\right)^{3}$$

Multiply 1152 and -2 to get -2304.

$$-2304\left(-4\right)^{3}$$

Calculate -4 to the power of 3 and get -64.

$$-2304\left(-64\right)$$

Multiply -2304 and -64 to get 147456.

$$147456$$

Factor

$$2^{14}\times 3^{2}$$