Solve -2^4+-2^3-5(-2^2)+12

$${ -2 }^{ 4 } + { -2 }^{ 3 } -5(- { 2 }^{ 2 } )+12$$

Evaluate

$$40$$

Solution Steps

Calculate -2 to the power of 4 and get 16.

$$16+\left(-2\right)^{3}-5\left(-2^{2}\right)+12$$

Calculate -2 to the power of 3 and get -8.

$$16-8-5\left(-2^{2}\right)+12$$

Subtract 8 from 16 to get 8.

$$8-5\left(-2^{2}\right)+12$$

Calculate 2 to the power of 2 and get 4.

$$8-5\left(-4\right)+12$$

Multiply 5 and -4 to get -20.

$$8-\left(-20\right)+12$$

The opposite of -20 is 20.

$$8+20+12$$

Add 8 and 20 to get 28.

$$28+12$$

Add 28 and 12 to get 40.

$$40$$

Factor

$$2^{3}\times 5$$