Solve left(y-0right)^2=40(x+5)

$${ \left(y-0 \right) }^{ 2 } =40(x+5)$$

Solve for x

$$x=\frac{y^{2}-200}{40}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 40 by x+5.

$$\left(y-0\right)^{2}=40x+200$$

Swap sides so that all variable terms are on the left hand side.

$$40x+200=\left(y-0\right)^{2}$$

Subtract 200 from both sides.

$$40x=\left(y-0\right)^{2}-200$$

Reorder the terms.

$$40x=y^{2}-200$$

Divide both sides by 40.

$$\frac{40x}{40}=\frac{y^{2}-200}{40}$$

Dividing by 40 undoes the multiplication by 40.

$$x=\frac{y^{2}-200}{40}$$

Divide y^{2}-200 by 40.

$$x=\frac{y^{2}}{40}-5$$

Solve for y (complex solution)

$$y=-2\sqrt{10\left(x+5\right)}$$

$$y=2\sqrt{10\left(x+5\right)}$$

Solve for y

$$y=2\sqrt{10\left(x+5\right)}$$

$$y=-2\sqrt{10\left(x+5\right)}\text{, }x\geq -5$$