Solve left(x-6right)^2=40

$${ \left(x-6 \right) }^{ 2 } =40$$

Solve for x

$$x=2\sqrt{10}+6\approx 12.32455532$$

$$x=6-2\sqrt{10}\approx -0.32455532$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x-6=2\sqrt{10} x-6=-2\sqrt{10}$$

Add 6 to both sides of the equation.

$$x-6-\left(-6\right)=2\sqrt{10}-\left(-6\right) x-6-\left(-6\right)=-2\sqrt{10}-\left(-6\right)$$

Subtracting -6 from itself leaves 0.

$$x=2\sqrt{10}-\left(-6\right) x=-2\sqrt{10}-\left(-6\right)$$

Subtract -6 from 2\sqrt{10}.

$$x=2\sqrt{10}+6$$

Subtract -6 from -2\sqrt{10}.

$$x=6-2\sqrt{10}$$

The equation is now solved.

$$x=2\sqrt{10}+6 x=6-2\sqrt{10}$$