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x^{2}-6x+9-3
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
x^{2}-6x+6
Subtract 3 from 9 to get 6.
x^{2}-6x+9-3
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
x^{2}-6x+6
Subtract 3 from 9 to get 6.