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x^{2}-2x+1-\left(\sqrt{5}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
x^{2}-2x+1-5
The square of \sqrt{5} is 5.
x^{2}-2x-4
Subtract 5 from 1 to get -4.
\left(x-1-\sqrt{5}\right)\left(x-1+\sqrt{5}\right)
The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).