Solve left(x-1^right)^2-25

$${ \left(x- { 1 }^{ } \right) }^{ 2 } -25$$

Evaluate

$$\left(x-6\right)\left(x+4\right)$$

Solution Steps

Calculate 1 to the power of 1 and get 1.

$$\left(x-1\right)^{2}-25$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.

$$x^{2}-2x+1-25$$

Subtract 25 from 1 to get -24.

$$x^{2}-2x-24$$

Expand

$$x^{2}-2x-24$$

Solution Steps

Calculate 1 to the power of 1 and get 1.

$$\left(x-1\right)^{2}-25$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.

$$x^{2}-2x+1-25$$

Subtract 25 from 1 to get -24.

$$x^{2}-2x-24$$