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x^{2}-\frac{14}{3}x+\frac{49}{9}-\frac{49}{36}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-\frac{7}{3}\right)^{2}.
x^{2}-\frac{14}{3}x+\frac{49}{12}
Subtract \frac{49}{36} from \frac{49}{9} to get \frac{49}{12}.
x^{2}-\frac{14}{3}x+\frac{49}{9}-\frac{49}{36}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-\frac{7}{3}\right)^{2}.
x^{2}-\frac{14}{3}x+\frac{49}{12}
Subtract \frac{49}{36} from \frac{49}{9} to get \frac{49}{12}.