Solve left(x+7right)^2=x^2+49

$${ \left(x+7 \right) }^{ 2 } = { x }^{ 2 } +49$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+7\right)^{2}.

$$x^{2}+14x+49=x^{2}+49$$

Subtract x^{2} from both sides.

$$x^{2}+14x+49-x^{2}=49$$

Combine x^{2} and -x^{2} to get 0.

$$14x+49=49$$

Subtract 49 from both sides.

$$14x=49-49$$

Subtract 49 from 49 to get 0.

$$14x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 14 is not equal to 0, x must be equal to 0.

$$x=0$$