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\left(x+4\right)^{2}=0
To solve the inequality, factor the left hand side. Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-8±\sqrt{8^{2}-4\times 1\times 16}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 8 for b, and 16 for c in the quadratic formula.
x=\frac{-8±0}{2}
Do the calculations.
x=-4
Solutions are the same.
\left(x+4\right)^{2}>0
Rewrite the inequality by using the obtained solutions.
x\neq -4
Inequality holds for x\neq -4.