Solve left(x+3right)^2=(x-3)(x+13)

$${ \left(x+3 \right) }^{ 2 } =(x-3)(x+13)$$

Solve for x

$$x=12$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.

$$x^{2}+6x+9=\left(x-3\right)\left(x+13\right)$$

Use the distributive property to multiply x-3 by x+13 and combine like terms.

$$x^{2}+6x+9=x^{2}+10x-39$$

Subtract x^{2} from both sides.

$$x^{2}+6x+9-x^{2}=10x-39$$

Combine x^{2} and -x^{2} to get 0.

$$6x+9=10x-39$$

Subtract 10x from both sides.

$$6x+9-10x=-39$$

Combine 6x and -10x to get -4x.

$$-4x+9=-39$$

Subtract 9 from both sides.

$$-4x=-39-9$$

Subtract 9 from -39 to get -48.

$$-4x=-48$$

Divide both sides by -4.

$$x=\frac{-48}{-4}$$

Divide -48 by -4 to get 12.

$$x=12$$