Solve left(x+3right)^2+3=9

$${ \left(x+3 \right) }^{ 2 } +3=9$$

Solve for x

$$x=\sqrt{6}-3\approx -0.550510257$$

$$x=-\left(\sqrt{6}+3\right)\approx -5.449489743$$

Steps by Finding Square Root

Subtract 3 from both sides of the equation.

$$\left(x+3\right)^{2}+3-3=9-3$$

Subtracting 3 from itself leaves 0.

$$\left(x+3\right)^{2}=9-3$$

Subtract 3 from 9.

$$\left(x+3\right)^{2}=6$$

Take the square root of both sides of the equation.

$$x+3=\sqrt{6} x+3=-\sqrt{6}$$

Subtract 3 from both sides of the equation.

$$x+3-3=\sqrt{6}-3 x+3-3=-\sqrt{6}-3$$

Subtracting 3 from itself leaves 0.

$$x=\sqrt{6}-3 x=-\sqrt{6}-3$$