Solve for x
x=5
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x^{2}+4x+4-x^{2}=24
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.
4x+4=24
Combine x^{2} and -x^{2} to get 0.
4x=24-4
Subtract 4 from both sides.
4x=20
Subtract 4 from 24 to get 20.
x=\frac{20}{4}
Divide both sides by 4.
x=5
Divide 20 by 4 to get 5.
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