Solve left(x+10right)^2+-22=0

$${ \left(x+10 \right) }^{ 2 } +-22 = 0$$

Solve for x

$$x=\sqrt{22}-10\approx -5.30958424$$

$$x=-\left(\sqrt{22}+10\right)\approx -14.69041576$$

Steps by Finding Square Root

Add 22 to both sides of the equation.

$$\left(x+10\right)^{2}-22+22=22$$

Subtracting 22 from itself leaves 0.

$$\left(x+10\right)^{2}=22$$

Take the square root of both sides of the equation.

$$x+10=\sqrt{22} x+10=-\sqrt{22}$$

Subtract 10 from both sides of the equation.

$$x+10-10=\sqrt{22}-10 x+10-10=-\sqrt{22}-10$$

Subtracting 10 from itself leaves 0.

$$x=\sqrt{22}-10 x=-\sqrt{22}-10$$