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x^{3}+3x^{2}+3x+1-\left(x-1\right)^{3}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+1\right)^{3}.
x^{3}+3x^{2}+3x+1-\left(x^{3}-3x^{2}+3x-1\right)
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-1\right)^{3}.
x^{3}+3x^{2}+3x+1-x^{3}+3x^{2}-3x+1
To find the opposite of x^{3}-3x^{2}+3x-1, find the opposite of each term.
3x^{2}+3x+1+3x^{2}-3x+1
Combine x^{3} and -x^{3} to get 0.
6x^{2}+3x+1-3x+1
Combine 3x^{2} and 3x^{2} to get 6x^{2}.
6x^{2}+1+1
Combine 3x and -3x to get 0.
6x^{2}+2
Add 1 and 1 to get 2.
x^{3}+3x^{2}+3x+1-\left(x-1\right)^{3}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+1\right)^{3}.
x^{3}+3x^{2}+3x+1-\left(x^{3}-3x^{2}+3x-1\right)
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-1\right)^{3}.
x^{3}+3x^{2}+3x+1-x^{3}+3x^{2}-3x+1
To find the opposite of x^{3}-3x^{2}+3x-1, find the opposite of each term.
3x^{2}+3x+1+3x^{2}-3x+1
Combine x^{3} and -x^{3} to get 0.
6x^{2}+3x+1-3x+1
Combine 3x^{2} and 3x^{2} to get 6x^{2}.
6x^{2}+1+1
Combine 3x and -3x to get 0.
6x^{2}+2
Add 1 and 1 to get 2.