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\left(x+1\right)^{2}-1.16+1.16=1.16
Add 1.16 to both sides of the equation.
\left(x+1\right)^{2}=1.16
Subtracting 1.16 from itself leaves 0.
x+1=\frac{\sqrt{29}}{5} x+1=-\frac{\sqrt{29}}{5}
Take the square root of both sides of the equation.
x+1-1=\frac{\sqrt{29}}{5}-1 x+1-1=-\frac{\sqrt{29}}{5}-1
Subtract 1 from both sides of the equation.
x=\frac{\sqrt{29}}{5}-1 x=-\frac{\sqrt{29}}{5}-1
Subtracting 1 from itself leaves 0.