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x^{3}+\frac{1}{2}x^{2}+\frac{1}{12}x+\frac{1}{216}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+\frac{1}{6}\right)^{3}.
x^{3}+\frac{1}{2}x^{2}+\frac{1}{12}x+\frac{1}{216}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+\frac{1}{6}\right)^{3}.