Solve left(a+bright)^255528

$${ \left(a+b \right) }^{ 2 } 55528$$

Evaluate

$$55528\left(a+b\right)^{2}$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+b\right)^{2}.

$$\left(a^{2}+2ab+b^{2}\right)\times 55528$$

Use the distributive property to multiply a^{2}+2ab+b^{2} by 55528.

$$55528a^{2}+111056ab+55528b^{2}$$

Expand

$$55528a^{2}+111056ab+55528b^{2}$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+b\right)^{2}.

$$\left(a^{2}+2ab+b^{2}\right)\times 55528$$

Use the distributive property to multiply a^{2}+2ab+b^{2} by 55528.

$$55528a^{2}+111056ab+55528b^{2}$$