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a^{3}+21a^{2}+147a+343-64
Use binomial theorem \left(p+q\right)^{3}=p^{3}+3p^{2}q+3pq^{2}+q^{3} to expand \left(a+7\right)^{3}.
a^{3}+21a^{2}+147a+279
Subtract 64 from 343 to get 279.
a^{3}+21a^{2}+147a+343-64
Use binomial theorem \left(p+q\right)^{3}=p^{3}+3p^{2}q+3pq^{2}+q^{3} to expand \left(a+7\right)^{3}.
a^{3}+21a^{2}+147a+279
Subtract 64 from 343 to get 279.