Solve left(8x-4right)^2=0

$${ \left(8x-4 \right) }^{ 2 } =0$$

Solve for x

$$x=\frac{1}{2}=0.5$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$8x-4=0 8x-4=0$$

Add 4 to both sides of the equation.

$$8x-4-\left(-4\right)=-\left(-4\right) 8x-4-\left(-4\right)=-\left(-4\right)$$

Subtracting -4 from itself leaves 0.

$$8x=-\left(-4\right) 8x=-\left(-4\right)$$

Subtract -4 from 0.

$$8x=4$$

Divide both sides by 8.

$$\frac{8x}{8}=\frac{4}{8} \frac{8x}{8}=\frac{4}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$x=\frac{4}{8} x=\frac{4}{8}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$x=\frac{1}{2}$$