Solve left(6x+2right)^2-10=0

$${ \left(6x+2 \right) }^{ 2 } -10=0$$

Solve for x

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3}\approx 0.193712943$$

$$x=-\frac{\sqrt{10}}{6}-\frac{1}{3}\approx -0.86037961$$

Steps by Finding Square Root

Add 10 to both sides of the equation.

$$\left(6x+2\right)^{2}-10+10=10$$

Subtracting 10 from itself leaves 0.

$$\left(6x+2\right)^{2}=10$$

Take the square root of both sides of the equation.

$$6x+2=\sqrt{10} 6x+2=-\sqrt{10}$$

Subtract 2 from both sides of the equation.

$$6x+2-2=\sqrt{10}-2 6x+2-2=-\sqrt{10}-2$$

Subtracting 2 from itself leaves 0.

$$6x=\sqrt{10}-2 6x=-\sqrt{10}-2$$

Subtract 2 from \sqrt{10}.

$$6x=\sqrt{10}-2$$

Subtract 2 from -\sqrt{10}.

$$6x=-\sqrt{10}-2$$

Divide both sides by 6.

$$\frac{6x}{6}=\frac{\sqrt{10}-2}{6} \frac{6x}{6}=\frac{-\sqrt{10}-2}{6}$$

Dividing by 6 undoes the multiplication by 6.

$$x=\frac{\sqrt{10}-2}{6} x=\frac{-\sqrt{10}-2}{6}$$

Divide \sqrt{10}-2 by 6.

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3}$$

Divide -\sqrt{10}-2 by 6.

$$x=-\frac{\sqrt{10}}{6}-\frac{1}{3}$$

The equation is now solved.

$$x=\frac{\sqrt{10}}{6}-\frac{1}{3} x=-\frac{\sqrt{10}}{6}-\frac{1}{3}$$