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36-24\sqrt{3}+4\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(6-2\sqrt{3}\right)^{2}.
36-24\sqrt{3}+4\times 3
The square of \sqrt{3} is 3.
36-24\sqrt{3}+12
Multiply 4 and 3 to get 12.
48-24\sqrt{3}
Add 36 and 12 to get 48.
36-24\sqrt{3}+4\left(\sqrt{3}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(6-2\sqrt{3}\right)^{2}.
36-24\sqrt{3}+4\times 3
The square of \sqrt{3} is 3.
36-24\sqrt{3}+12
Multiply 4 and 3 to get 12.
48-24\sqrt{3}
Add 36 and 12 to get 48.