Solve left(4-4right)^2+left(-2+2right)^2+left(0-5right)^2

$${ \left(4-4 \right) }^{ 2 } + { \left(-2+2 \right) }^{ 2 } + { \left(0-5 \right) }^{ 2 }$$

Evaluate

$$25$$

Solution Steps

Subtract 4 from 4 to get 0.

$$0^{2}+\left(-2+2\right)^{2}+\left(0-5\right)^{2}$$

Calculate 0 to the power of 2 and get 0.

$$0+\left(-2+2\right)^{2}+\left(0-5\right)^{2}$$

Add -2 and 2 to get 0.

$$0+0^{2}+\left(0-5\right)^{2}$$

Calculate 0 to the power of 2 and get 0.

$$0+0+\left(0-5\right)^{2}$$

Add 0 and 0 to get 0.

$$\left(0-5\right)^{2}$$

Subtract 5 from 0 to get -5.

$$\left(-5\right)^{2}$$

Calculate -5 to the power of 2 and get 25.

$$25$$

Factor

$$5^{2}$$