Solve left(4*-1right)^2-(4*-1)*(4*+1)+28=-10

$${ \left(4 \times -1 \right) }^{ 2 } -(4 \times -1) \times (4 \times +1)+28=-10$$

Verify

Solution Steps

Multiply 4 and -1 to get -4.

$$\left(-4\right)^{2}-4\left(-1\right)\times 4\times 1+28=-10$$

Calculate -4 to the power of 2 and get 16.

$$16-4\left(-1\right)\times 4\times 1+28=-10$$

Multiply 4 and -1 to get -4.

$$16-\left(-4\times 4\right)+28=-10$$

Multiply -4 and 4 to get -16.

$$16-\left(-16\right)+28=-10$$

The opposite of -16 is 16.

$$16+16+28=-10$$

Add 16 and 16 to get 32.

$$32+28=-10$$

Add 32 and 28 to get 60.

$$60=-10$$

Compare 60 and -10.

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