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16\left(\sqrt{15}\right)^{2}-16\sqrt{15}\sqrt{39}+4\left(\sqrt{39}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4\sqrt{15}-2\sqrt{39}\right)^{2}.
16\times 15-16\sqrt{15}\sqrt{39}+4\left(\sqrt{39}\right)^{2}
The square of \sqrt{15} is 15.
240-16\sqrt{15}\sqrt{39}+4\left(\sqrt{39}\right)^{2}
Multiply 16 and 15 to get 240.
240-16\sqrt{585}+4\left(\sqrt{39}\right)^{2}
To multiply \sqrt{15} and \sqrt{39}, multiply the numbers under the square root.
240-16\sqrt{585}+4\times 39
The square of \sqrt{39} is 39.
240-16\sqrt{585}+156
Multiply 4 and 39 to get 156.
396-16\sqrt{585}
Add 240 and 156 to get 396.
396-16\times 3\sqrt{65}
Factor 585=3^{2}\times 65. Rewrite the square root of the product \sqrt{3^{2}\times 65} as the product of square roots \sqrt{3^{2}}\sqrt{65}. Take the square root of 3^{2}.
396-48\sqrt{65}
Multiply -16 and 3 to get -48.
16\left(\sqrt{15}\right)^{2}-16\sqrt{15}\sqrt{39}+4\left(\sqrt{39}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4\sqrt{15}-2\sqrt{39}\right)^{2}.
16\times 15-16\sqrt{15}\sqrt{39}+4\left(\sqrt{39}\right)^{2}
The square of \sqrt{15} is 15.
240-16\sqrt{15}\sqrt{39}+4\left(\sqrt{39}\right)^{2}
Multiply 16 and 15 to get 240.
240-16\sqrt{585}+4\left(\sqrt{39}\right)^{2}
To multiply \sqrt{15} and \sqrt{39}, multiply the numbers under the square root.
240-16\sqrt{585}+4\times 39
The square of \sqrt{39} is 39.
240-16\sqrt{585}+156
Multiply 4 and 39 to get 156.
396-16\sqrt{585}
Add 240 and 156 to get 396.
396-16\times 3\sqrt{65}
Factor 585=3^{2}\times 65. Rewrite the square root of the product \sqrt{3^{2}\times 65} as the product of square roots \sqrt{3^{2}}\sqrt{65}. Take the square root of 3^{2}.
396-48\sqrt{65}
Multiply -16 and 3 to get -48.