Solve left(4*2-3*1right)^2+18/4*2+1+24/4

$${ \left(4 \cdot 2-3 \cdot 1 \right) }^{ 2 } + \frac{ 18 }{ 4 \cdot 2+1 } + \frac{ 24 }{ 4 }$$

Evaluate

$$33$$

Solution Steps

Multiply 4 and 2 to get 8.

$$\left(8-3\times 1\right)^{2}+\frac{18}{4\times 2+1}+\frac{24}{4}$$

Multiply 3 and 1 to get 3.

$$\left(8-3\right)^{2}+\frac{18}{4\times 2+1}+\frac{24}{4}$$

Subtract 3 from 8 to get 5.

$$5^{2}+\frac{18}{4\times 2+1}+\frac{24}{4}$$

Calculate 5 to the power of 2 and get 25.

$$25+\frac{18}{4\times 2+1}+\frac{24}{4}$$

Multiply 4 and 2 to get 8.

$$25+\frac{18}{8+1}+\frac{24}{4}$$

Add 8 and 1 to get 9.

$$25+\frac{18}{9}+\frac{24}{4}$$

Divide 18 by 9 to get 2.

$$25+2+\frac{24}{4}$$

Add 25 and 2 to get 27.

$$27+\frac{24}{4}$$

Divide 24 by 4 to get 6.

$$27+6$$

Add 27 and 6 to get 33.

$$33$$

Factor

$$3\times 11$$