Solve left(3x-1right)^2+5=9x^2

$${ \left(3x-1 \right) }^{ 2 } +5=9 { x }^{ 2 }$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3x-1\right)^{2}.

$$9x^{2}-6x+1+5=9x^{2}$$

Add 1 and 5 to get 6.

$$9x^{2}-6x+6=9x^{2}$$

Subtract 9x^{2} from both sides.

$$9x^{2}-6x+6-9x^{2}=0$$

Combine 9x^{2} and -9x^{2} to get 0.

$$-6x+6=0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$-6x=-6$$

Divide both sides by -6.

$$x=\frac{-6}{-6}$$

Divide -6 by -6 to get 1.

$$x=1$$