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9x^{2}+6x+1-1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3x+1\right)^{2}.
9x^{2}+6x
Subtract 1 from 1 to get 0.
9x^{2}+6x+1-1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3x+1\right)^{2}.
9x^{2}+6x
Subtract 1 from 1 to get 0.