Solve {left(3+22/26right)}^2

$${ \left(3+2 \frac{ 2 }{ 26 } \right) }^{ 2 }$$

Evaluate

$$\frac{4356}{169}\approx 25.775147929$$

Solution Steps

Multiply 2 and 26 to get 52.

$$\left(3+\frac{52+2}{26}\right)^{2}$$

Add 52 and 2 to get 54.

$$\left(3+\frac{54}{26}\right)^{2}$$

Reduce the fraction \frac{54}{26} to lowest terms by extracting and canceling out 2.

$$\left(3+\frac{27}{13}\right)^{2}$$

Add 3 and \frac{27}{13} to get \frac{66}{13}.

$$\left(\frac{66}{13}\right)^{2}$$

Calculate \frac{66}{13} to the power of 2 and get \frac{4356}{169}.

$$\frac{4356}{169}$$

Factor

$$\frac{2 ^ {2} \cdot 3 ^ {2} \cdot 11 ^ {2}}{13 ^ {2}} = 25\frac{131}{169} = 25.775147928994084$$