Solve left(3*(-1)-1right)^2-(1-3*(-1))*(1+3*(-1))

$${ \left(3 \times (-1)-1 \right) }^{ 2 } -(1-3 \times (-1)) \times (1+3 \times (-1))$$

Evaluate

$$24$$

Solution Steps

Multiply 3 and -1 to get -3.

$$\left(-3-1\right)^{2}-\left(1-3\left(-1\right)\right)\left(1+3\left(-1\right)\right)$$

Subtract 1 from -3 to get -4.

$$\left(-4\right)^{2}-\left(1-3\left(-1\right)\right)\left(1+3\left(-1\right)\right)$$

Calculate -4 to the power of 2 and get 16.

$$16-\left(1-3\left(-1\right)\right)\left(1+3\left(-1\right)\right)$$

Multiply 3 and -1 to get -3.

$$16-\left(1-\left(-3\right)\right)\left(1+3\left(-1\right)\right)$$

The opposite of -3 is 3.

$$16-\left(1+3\right)\left(1+3\left(-1\right)\right)$$

Add 1 and 3 to get 4.

$$16-4\left(1+3\left(-1\right)\right)$$

Multiply 3 and -1 to get -3.

$$16-4\left(1-3\right)$$

Subtract 3 from 1 to get -2.

$$16-4\left(-2\right)$$

Multiply 4 and -2 to get -8.

$$16-\left(-8\right)$$

The opposite of -8 is 8.

$$16+8$$

Add 16 and 8 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$