Evaluate
18\left(\sqrt{3}+2\right)\approx 67.176914536
Expand
18 \sqrt{3} + 36 = 67.176914536
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9\left(\sqrt{3}\right)^{2}+18\sqrt{3}+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3\sqrt{3}+3\right)^{2}.
9\times 3+18\sqrt{3}+9
The square of \sqrt{3} is 3.
27+18\sqrt{3}+9
Multiply 9 and 3 to get 27.
36+18\sqrt{3}
Add 27 and 9 to get 36.
9\left(\sqrt{3}\right)^{2}+18\sqrt{3}+9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3\sqrt{3}+3\right)^{2}.
9\times 3+18\sqrt{3}+9
The square of \sqrt{3} is 3.
27+18\sqrt{3}+9
Multiply 9 and 3 to get 27.
36+18\sqrt{3}
Add 27 and 9 to get 36.
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