Solve left(2x-12right)^2=4x^2+48

$${ \left(2x-12 \right) }^{ 2 } =4 { x }^{ 2 } +48$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-12\right)^{2}.

$$4x^{2}-48x+144=4x^{2}+48$$

Subtract 4x^{2} from both sides.

$$4x^{2}-48x+144-4x^{2}=48$$

Combine 4x^{2} and -4x^{2} to get 0.

$$-48x+144=48$$

Subtract 144 from both sides.

$$-48x=48-144$$

Subtract 144 from 48 to get -96.

$$-48x=-96$$

Divide both sides by -48.

$$x=\frac{-96}{-48}$$

Divide -96 by -48 to get 2.

$$x=2$$