Solve left(2x-1right)^2-4x^2=0

$${ \left(2x-1 \right) }^{ 2 } -4 { x }^{ 2 } =0$$

Solve for x

$$x=\frac{1}{4}=0.25$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2x-1\right)^{2}.

$$4x^{2}-4x+1-4x^{2}=0$$

Combine 4x^{2} and -4x^{2} to get 0.

$$-4x+1=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-4x=-1$$

Divide both sides by -4.

$$x=\frac{-1}{-4}$$

Fraction \frac{-1}{-4} can be simplified to \frac{1}{4} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{4}$$