Solve left(2a+1right)^2pi

$${ \left(2a+1 \right) }^{ 2 } \pi$$

Evaluate

$$\pi \left(2a+1\right)^{2}$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(2a+1\right)^{2}.

$$\left(4a^{2}+4a+1\right)\pi$$

Use the distributive property to multiply 4a^{2}+4a+1 by \pi .

$$4a^{2}\pi +4a\pi +\pi$$

Expand

$$4\pi a^{2}+4\pi a+\pi$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(2a+1\right)^{2}.

$$\left(4a^{2}+4a+1\right)\pi$$

Use the distributive property to multiply 4a^{2}+4a+1 by \pi .

$$4a^{2}\pi +4a\pi +\pi$$