Solve left(20-5*3right)^2-3^4+22div11+sqrt[4]{2*20+135^0+5*8}

$${ \left(20-5 \times 3 \right) }^{ 2 } - { 3 }^{ 4 } +22 \div 11+ \sqrt[ 4 ]{ 2 \times 20+ { 135 }^{ 0 } +5 \times 8 }$$

Evaluate

$$-51$$

Solution Steps

Multiply 5 and 3 to get 15.

$$\left(20-15\right)^{2}-3^{4}+\frac{22}{11}+\sqrt[4]{2\times 20+135^{0}+5\times 8}$$

Subtract 15 from 20 to get 5.

$$5^{2}-3^{4}+\frac{22}{11}+\sqrt[4]{2\times 20+135^{0}+5\times 8}$$

Calculate 5 to the power of 2 and get 25.

$$25-3^{4}+\frac{22}{11}+\sqrt[4]{2\times 20+135^{0}+5\times 8}$$

Calculate 3 to the power of 4 and get 81.

$$25-81+\frac{22}{11}+\sqrt[4]{2\times 20+135^{0}+5\times 8}$$

Subtract 81 from 25 to get -56.

$$-56+\frac{22}{11}+\sqrt[4]{2\times 20+135^{0}+5\times 8}$$

Divide 22 by 11 to get 2.

$$-56+2+\sqrt[4]{2\times 20+135^{0}+5\times 8}$$

Add -56 and 2 to get -54.

$$-54+\sqrt[4]{2\times 20+135^{0}+5\times 8}$$

Do the multiplications.

$$-54+\sqrt[4]{40+135^{0}+40}$$

Calculate 135 to the power of 0 and get 1.

$$-54+\sqrt[4]{40+1+40}$$

Add 40 and 1 to get 41.

$$-54+\sqrt[4]{41+40}$$

Add 41 and 40 to get 81.

$$-54+\sqrt[4]{81}$$

Calculate \sqrt[4]{81} and get 3.

$$-54+3$$

Add -54 and 3 to get -51.

$$-51$$

Factor

$$-51$$