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4\left(\sqrt{6}\right)^{2}+20\sqrt{6}+25
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2\sqrt{6}+5\right)^{2}.
4\times 6+20\sqrt{6}+25
The square of \sqrt{6} is 6.
24+20\sqrt{6}+25
Multiply 4 and 6 to get 24.
49+20\sqrt{6}
Add 24 and 25 to get 49.
4\left(\sqrt{6}\right)^{2}+20\sqrt{6}+25
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2\sqrt{6}+5\right)^{2}.
4\times 6+20\sqrt{6}+25
The square of \sqrt{6} is 6.
24+20\sqrt{6}+25
Multiply 4 and 6 to get 24.
49+20\sqrt{6}
Add 24 and 25 to get 49.