{ \left(-2+ \sqrt{ 3 } \right) }^{ 2 } - \frac{ 1 }{ }
Evaluate
6-4\sqrt{3}\approx -0.92820323
Expand
6-4\sqrt{3}
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\left(-2+\sqrt{3}\right)^{2}-1
Divide 1 by 1 to get 1.
4-4\sqrt{3}+\left(\sqrt{3}\right)^{2}-1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(-2+\sqrt{3}\right)^{2}.
4-4\sqrt{3}+3-1
The square of \sqrt{3} is 3.
7-4\sqrt{3}-1
Add 4 and 3 to get 7.
6-4\sqrt{3}
Subtract 1 from 7 to get 6.
\left(-2+\sqrt{3}\right)^{2}-1
Divide 1 by 1 to get 1.
4-4\sqrt{3}+\left(\sqrt{3}\right)^{2}-1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(-2+\sqrt{3}\right)^{2}.
4-4\sqrt{3}+3-1
The square of \sqrt{3} is 3.
7-4\sqrt{3}-1
Add 4 and 3 to get 7.
6-4\sqrt{3}
Subtract 1 from 7 to get 6.
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