Solve {left(-2sqrt{7}right)}^2-4*4*1=

$${ \left(-2 \sqrt{ 7 } \right) }^{ 2 } -4 \times 4 \times 1=$$

Evaluate

$$12$$

Solution Steps

Expand \left(-2\sqrt{7}\right)^{2}.

$$\left(-2\right)^{2}\left(\sqrt{7}\right)^{2}-4\times 4\times 1$$

Calculate -2 to the power of 2 and get 4.

$$4\left(\sqrt{7}\right)^{2}-4\times 4\times 1$$

The square of \sqrt{7} is 7.

$$4\times 7-4\times 4\times 1$$

Multiply 4 and 7 to get 28.

$$28-4\times 4\times 1$$

Multiply 4 and 4 to get 16.

$$28-16\times 1$$

Multiply 16 and 1 to get 16.

$$28-16$$

Subtract 16 from 28 to get 12.

$$12$$

Factor

$$2^{2}\times 3$$