Solve {left(-1/3right)}^-2+4*-1^2019-left|-2^3right|+left(pi-5right)^0

$${ \left(- \frac{ 1 }{ 3 } \right) }^{ -2 } +4 \times { -1 }^{ 2019 } - \left| - { 2 }^{ 3 } \right| + { \left( \pi -5 \right) }^{ 0 }$$

Evaluate

$$-2$$

Solution Steps

Calculate -\frac{1}{3} to the power of -2 and get 9.

$$9+4\left(-1\right)^{2019}-|-2^{3}|+\left(\pi -5\right)^{0}$$

Calculate -1 to the power of 2019 and get -1.

$$9+4\left(-1\right)-|-2^{3}|+\left(\pi -5\right)^{0}$$

Multiply 4 and -1 to get -4.

$$9-4-|-2^{3}|+\left(\pi -5\right)^{0}$$

Subtract 4 from 9 to get 5.

$$5-|-2^{3}|+\left(\pi -5\right)^{0}$$

Calculate 2 to the power of 3 and get 8.

$$5-|-8|+\left(\pi -5\right)^{0}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -8 is 8.

$$5-8+\left(\pi -5\right)^{0}$$

Subtract 8 from 5 to get -3.

$$-3+\left(\pi -5\right)^{0}$$

Calculate \pi -5 to the power of 0 and get 1.

$$-3+1$$

Add -3 and 1 to get -2.

$$-2$$

Factor

$$-2$$