Solve {left(-1/3right)}^-1+sqrt{3}-2-left(pi-3.14right)^0+2sin(60^circ)

$${ \left(- \frac{ 1 }{ 3 } \right) }^{ -1 } + \sqrt{ 3 } -2- { \left( \pi -3.14 \right) }^{ 0 } +2 \sin ( 60 ^ { \circ } )$$

Evaluate

$$2\left(\sqrt{3}-3\right)\approx -2.535898385$$

Solution Steps

Calculate -\frac{1}{3} to the power of -1 and get -3.

$$-3+\sqrt{3}-2-\left(\pi -3.14\right)^{0}+2\sin(60)$$

Subtract 2 from -3 to get -5.

$$-5+\sqrt{3}-\left(\pi -3.14\right)^{0}+2\sin(60)$$

Calculate \pi -3.14 to the power of 0 and get 1.

$$-5+\sqrt{3}-1+2\sin(60)$$

Subtract 1 from -5 to get -6.

$$-6+\sqrt{3}+2\sin(60)$$

Get the value of \sin(60) from trigonometric values table.

$$-6+\sqrt{3}+2\times \frac{\sqrt{3}}{2}$$

Cancel out 2 and 2.

$$-6+\sqrt{3}+\sqrt{3}$$

Combine \sqrt{3} and \sqrt{3} to get 2\sqrt{3}.

$$-6+2\sqrt{3}$$