Solve left(x^-3right)^2

$${ \left( { x }^{ -3 } \right) }^{ 2 }$$

Evaluate

$$\frac{1}{x^{6}}$$

Steps for Raising Power to Another Power

Use the rules of exponents to simplify the expression.

$$\left(x^{-3}\right)^{2}$$

To raise a power to another power, multiply the exponents.

$$x^{-3\times 2}$$

Multiply -3 times 2.

$$\frac{1}{x^{6}}$$

Differentiate w.r.t. x

$$-\frac{6}{x^{7}}$$

Steps Using Chain Rule

If F is the composition of two differentiable functions f\left(u\right) and u=g\left(x\right), that is, if F\left(x\right)=f\left(g\left(x\right)\right), then the derivative of F is the derivative of f with respect to u times the derivative of g with respect to x, that is, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$2\left(x^{-3}\right)^{2-1}\frac{\mathrm{d}}{\mathrm{d}x}(x^{-3})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\left(x^{-3}\right)^{1}\left(-3\right)x^{-3-1}$$

Simplify.

$$-6x^{-4}\left(x^{-3}\right)^{1}$$

For any term t, t^{1}=t.

$$-6x^{-4}x^{-3}$$